Hi,
I have got the following project : http://www.datafilehost.com/d/3e0d49d0
The main.cpp file in it reads as follows :
#include <QGuiApplication>
#include <QQuickView>
int main(int argc, char* argv[])
{
QGuiApplication app(argc,argv);
QQuickView view;
view.setSource(QUrl(":/main.qml"));
view.setResizeMode(QQuickView::SizeRootObjectToView);
view.show();
return app.exec();
}
The qml is in main.qml which I have added to the resource:
<RCC>
<qresource prefix="/">
<file>main.qml</file>
</qresource>
</RCC>
But I still get an error :
Starting F:\Code\Qt\build-RapidConcepts-Desktop_Qt_5_2_1_MSVC2012_32bit-Debug\debug\RapidConcepts.exe…
QML debugging is enabled. Only use this in a safe environment.
file:///F:/Code/Qt/build-RapidConcepts-Desktop_Qt_5_2_1_MSVC2012_32bit-Debug/:/main.qml: File not found
1. There is no prefix for the resource. I have accessed it using the propoer qrc syntax. Yet I do not get why its unable to find it.
2. I want to make this application a mixed QML and C++ application. So when I created the project I got this class by default which was used in main.cpp :
#ifndef QTQUICK2APPLICATIONVIEWER_H
#define QTQUICK2APPLICATIONVIEWER_H
#include <QtQuick/QQuickView>
class QtQuick2ApplicationViewer : public QQuickView
{
Q_OBJECT
public:
explicit QtQuick2ApplicationViewer(QWindow *parent = 0);
virtual ~QtQuick2ApplicationViewer();
void setMainQmlFile(const QString &file);
void addImportPath(const QString &path);
void showExpanded();
private:
class QtQuick2ApplicationViewerPrivate *d;
};
Why do I have to use this class at all. Cant I just use QQuickView directly as in the code I have given at the top of this post ? Why does Qt generate this extra class at all ?
↧
