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Connect SpinBox to Slider (Dynamic Qml) [SOLVED]

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Hi, guys. Here is a simple of dynamically creating many pairs of SpinBox and Sliders, I want to connect the value of each SpinBox to the value of it’s corresponding Slider. import QtQuick 2.3 import QtQuick.Controls 1.2   ApplicationWindow {     visible: true     width: 400     height: 300     color: Qt.rgba(0, 0, 0, 1)       function createControl(itemType, where)     {         return Qt.createQmlObject("import QtQuick.Controls 1.2; "                                   + itemType                                   + " {}",                                   where,                                   "ApplicationWindow")     }       Component.onCompleted: {         // Create some controls.         for (var i = 0; i < 10; i++) {             var slider = createControl("Slider", grid)             var spinBox = createControl("SpinBox", grid)               // Connect the SpinBox to the Slider.             // This is what I want but doesn't work.                         // slider.valueChanged.connect(spinBox.setValue)             // spinBox.valueChanged.connect(slider.setValue)         }     }       Grid {         id: grid         columns: 2         anchors.fill: parent     } } Some ideas?

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