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Connect SpinBox to Slider (Dynamic Qml) [SOLVED]

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Ok, solved. Here is the code: import QtQuick 2.3 import QtQuick.Controls 1.2   ApplicationWindow {     id: appWindow     visible: true     width: 400     height: 300     color: Qt.rgba(0, 0, 0, 1)       property var sliders: []     property var spinBoxes: []       function createControl(itemType, where)     {         return Qt.createQmlObject("import QtQuick.Controls 1.2; "                                   + itemType                                   + " {}",                                   where,                                   "ApplicationWindow")     }       function spinBoxChanged()     {         for (var spinBox in appWindow.spinBoxes)             appWindow.sliders[spinBox].value =                     appWindow.spinBoxes[spinBox].value     }       function sliderChanged()     {         for (var sliders in appWindow.sliders)             appWindow.spinBoxes[sliders].value =                     appWindow.sliders[sliders].value     }       Component.onCompleted: {         // Create some controls.         for (var i = 0; i < 10; i++) {             var slider = createControl("Slider", grid)             var spinBox = createControl("SpinBox", grid)               // Connect the SpinBox to the Slider.             appWindow.sliders.push(slider)             appWindow.spinBoxes.push(spinBox)               slider.onValueChanged.connect(appWindow.sliderChanged)             spinBox.onValueChanged.connect(appWindow.spinBoxChanged)         }     }       Grid {         id: grid         columns: 2         anchors.fill: parent     } }

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